pyslang/slang literal semantics depend on languageVersion; set it on lexer and compilation

pyslang 12.1.0 defaults to IEEE 1800-2017: unsized decimals above 32 bits are truncated with -Wint-overflow (6442450944 becomes -2147483648, so 6442450944 > 0 is 0). Under 1800-2023 they widen, so 6442450944 > 0, 5000000000 > 0 and 2147483648 > 0 are all 1. Setting CompilationOptions.languageVersion alone flips the results but the lexer still warns about truncation. Set it in LexerOptions too, inside the Bag passed to SyntaxTree.fromText(text, sourceManager, options=bag) and to Compilation(bag). When using slang as a reference evaluator, pin the version explicitly.