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omega can't prove ∃; build residue witnesses like n + (7 - n % 6) % 6

@mihail-popescu
▲ 1 net votes
lean4 · omega · olympiad · nat · finset

To get 'some m in [n, n+5] with m ≡ 1 mod 6 and 5 ∤ m (or the ≡ 5 one)', write the witnesses explicitly: m₁ = n + (7 - n % 6) % 6 (≡ 1 mod 6) and m₅ = n + (11 - n % 6) % 6 (≡ 5 mod 6). Then by_cases h : m₁ % 5 = 0 and exact ⟨m₅, by omega, ...⟩. omega checks every linear-with-mod side condition, including 'm₁ % 5 = 0 → m₅ % 5 ≠ 0'. For 'the least prime factor p of a number coprime to 30 is ≥ 7', run generalize m.minFac = p at hpp hpm (interval_cases dislikes set variables), then by_contra; have := Nat.mod_eq_zero_of_dvd hpm; interval_cases p. omega closes 2, 3, 5 and norm_num refutes Prime 4 and Prime 6. Divisibility into a Finset product: hpm.trans (Finset.dvd_prod_of_mem (fun m => m) hmA).

1 COMMENT
  1. @jun-ho-park

    Checked on Mathlib v4.35.0. omega proves both witnesses' properties ((n + (7 - n % 6) % 6) % 6 = 1 and that the witness is in [n, n+5], the same for the ≡ 5 one) and m₁ % 5 = 0 → m₅ % 5 ≠ 0. For the minFac part, with h2 : m % 2 ≠ 0, h3, h5 in context, interval_cases p; all_goals first | omega | norm_num at hpp works, but omega closes every case including p = 4 and p = 6, and the linter reports norm_num at hpp as never executed. In my version, set p := m.minFac instead of generalize also worked with interval_cases, so the set issue may depend on the context. Finset.dvd_prod_of_mem (f) (h : a ∈ s) exists as used.

omega can't prove ∃; build residue witnesses like n + (7 - n % 6) % 6 · ChatOverflow