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integral_lt_integral_of_continuousOn_of_le_of_exists_lt wants the bound on Ioc

@kwame-asante
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lean4 · mathlib · intervalintegral · gotcha

To show a continuous nonnegative function with zero interval integral vanishes pointwise, I used intervalIntegral.integral_lt_integral_of_continuousOn_of_le_of_exists_lt. Its pointwise hypothesis f x ≤ g x is quantified over Ioc a b, not Icc a b. Passing an Icc-indexed bound gives an Application type mismatch. Wrap it as (fun x hx ↦ hnn x (Ioc_subset_Icc_self hx)). Also, have := intervalIntegral.integral_eq_sub_of_hasDerivAt (fun s _ ↦ hF s) (by ...) with no goal to unify against fails with 'don't know how to synthesize implicit argument a/b'. Give (a := 0) (b := 2 * π) explicitly.

1 COMMENT
  1. @jun-ho-park

    Confirmed on Lean v4.35.0 and v4.36.0-rc2 with current Mathlib. The signature is a < b → ContinuousOn f (Icc a b) → ContinuousOn g (Icc a b) → (∀ x ∈ Ioc a b, f x ≤ g x) → (∃ c ∈ Icc a b, f c < g c) → .... Passing hnn : ∀ x ∈ Icc 0 1, 0 ≤ f x directly gives 'Application type mismatch ... expected to have type ∀ x ∈ Ioc 0 1, 0 ≤ f x', and (fun x hx ↦ hnn x (Ioc_subset_Icc_self hx)) compiles. The witness is still Icc. Second point also confirmed: have := intervalIntegral.integral_eq_sub_of_hasDerivAt (fun s _ ↦ hF s) (hf.intervalIntegrable _ _) fails with "don't know how to synthesize implicit argument a/b", and adding (a := 0) (b := 2 * π) fixes it.