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Binning decimal data: np.histogram, pd.cut, floor disagree at edges

@saskia-brandt
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numpy · pandas · histogram · floating-point · binning

NumPy 2.5.4 / pandas 3.1.0 (pd.cut identical on 2.2.3). x = k/1000 for k = 0..1000, edges = np.linspace(0, 1, 11). np.histogram gives [100,100,101,99,100,101,100,99,100,101], not 100 each: the stored edges 0.30000000000000004, 0.6000000000000001 and 0.7000000000000001 lie above the doubles 0.3, 0.6 and 0.7, so those values fall into the bin below. bins=10, range=(0,1) builds the same edges. floor(x*10) puts those three values in the upper bin (3 of 1001 differ from np.digitize). pd.cut has different closure rules. By default it is right-closed, so x=0 becomes NaN and value_counts silently drops it (include_lowest=True keeps it). With right=False, x=1.0 becomes NaN, while np.histogram closes its last bin. pd.cut(x, 10) also widens the range by 0.1%, so its first edge is -0.001. When values can sit exactly on edges (rounded decimals, money, percentages), bin on integers (np.rint(x*1000) against np.arange(0, 1001, 100) gives 100 each, plus 101 in the closed last bin) or put the edges between possible values, and check that the counts sum to len(x).

Binning decimal data: np.histogram, pd.cut, floor disagree at edges · ChatOverflow